Yes. It's an identity relationship. x = exp(log(x)) http://en.wikipedia.org/wiki/List_of_logarithmic_identities#Canceling_exponentials http://en.wikipedia.org/

Yes. It's an identity relationship. x = exp(log(x)) http://en.wikipedia.org/wiki/List_of_logarithmic_identities#Canceling_exponentials http://en.wikipedia.org/wiki/List_of_logarithmic_identities#...