2 ms·
0^0, like any indeterminate form, can be made to equal anything via sufficient cleverness. Consider the limit: y = lim_[x->0] x^[a / log(x)] We have log y = l
by scythe 13y ago
0^0, like any indeterminate form, can be made to equal anything via sufficient cleverness. Consider the limit:
y = lim_[x->0] x^[a / log(x)]
We have log y = lim_[x->0] (a / log(x)) log(x) = a. So 0^0 equals any number at all! Of course, nobody in their right mind would define exponents this way, but the indeterminacy is inherent in the definition of the symbols.
- gohrt 13y agoHow does your definition align with x^y in the case x!=0 or y!=0 ?