3 ms·
Sorry - was away for a while. The drag FORCE will be the same, but the lighter car will deaccel faster as I clearly stated above. F=m*a thus: F/m = a Think of
by squigs25 13y ago
Sorry - was away for a while. The drag FORCE will be the same, but the lighter car will deaccel faster as I clearly stated above.
F=m*a
thus: F/m = a
Think of it like this: it's really easy to push a car that weighs one pound. Much harder to push a car that weighs 1000 pounds.
The momentum advantage was explained in the first point.