Nothing about the cast is "required". However, it's good practice because the cast explicitly acknowledges the function has a return value that we're throwing

Nothing about the cast is "required". However, it's good practice because the cast explicitly acknowledges the function has a return value that we're throwing out. Looking at the following function call: (void)create_widget(&widget); It's clear that `create_widget` returns some value -- it's probably an error code that tells us whether the widget creation was successful. The source code here says "I know this function returns an important value, but I'm going to disregard it here". This could be useful for debugging if you find that, for example, an error condition is being handled improperly (e.g. "oh, we're obviously throwing out the return value of this function, which we shouldn't be doing"). This function call is much less informative: create_widget(&widget);