3 ms·
What about e^(i*pi) = -1?
by pge 13y ago
What about e^(i*pi) = -1?
- liquidise 13y agoWhile this relationship is profound, i'm not sure it has led to any industry or academic shifts in understanding. Every equation on this list has single handedly expanded a respective field of study by its discovery.
- Jach 13y agoCovered by Fourier Transforms. The equations for Nash Equilibrium and Fermat's Little Theorem are two I would have liked to see.
- nextos 13y agoYes, I think Nash equilibrium will be way more influential in the long-term than Black-Scholes.
- aswanson 13y agoNeither one of them should be on there. Both rest upon the false assumption of human rationality. They are delusions masquerading as mathematical truth.
- consz 13y agoBlack Scholes doesn't assume rational market participants.
- justincormack 13y agoIt does make other bogus assumptions though. Normal distributions, risk free interest rates,...
- wreegab 13y agoI thought the problem with Black-Scholes is that it didn't factor in the use of Black-Scholes by participants.
- igravious 13y agoThat's an interesting perspective. And it's a perspective that would be familiar to any student of cybernetics and social systems theory: http://en.wikipedia.org/wiki/Second-order_cybernetics http://en.wikipedia.org/wiki/Second-order_cybernetics so-called second order cybernetics. Fascinating stuff I think.
- noobermin 13y agoOne could argue that with i^2=-1 and the taylor expansion of sine and cosine and the exponential, one get's that.