3 ms·
Right, in ideal hardware. The problem is that in order to transmit an ideal square wave, you need infinite bandwidth. The problem being that any real circuit h
by a-priori 13y ago
Right, in ideal hardware. The problem is that in order to transmit an ideal square wave, you need infinite bandwidth.
The problem being that any real circuit has a finite band it operates on. It will filter the components of the wave that are outside of its bandwidth, leading to 'ringing' artifacts (Gibbs phenomenon).
- lutusp 13y ago> Right, in ideal hardware. The problem is that in order to transmit an ideal square wave, you need infinite bandwidth. On the contrary. An ideal square wave's higher harmonics decline rather quickly: http://en.wikipedia.org/wiki/Square_wave#Examining_the_square_wave http://en.wikipedia.org/wiki/Square_wave#Examining_the_squar... In other words, there's enough energy to cause problems at 2, 6, 10 ... times f, but at rapidly declining levels. > It will filter the components of the wave that are outside of its bandwidth, leading to 'ringing' artifacts ... Ringing artifacts are present in a system whose bandwidth rolls off abruptly. It's less significant in a system with a gradual drop-off in response, like a piece of wire acting as a broadband antenna.