3 ms·
For this and the "general" definition to coincide, the ring in question has to be a unique factorization domain, which the integers are an example of. In any bi
by pavelrub 13y ago
For this and the "general" definition to coincide, the ring in question has to be a unique factorization domain, which the integers are an example of. In any bigger subset of rings (integral domains or general commutative rings), there are rings for which this doesn't hold.