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The rational roots of integers will cause interesting interactions, because when you multiply them you get back integers. In other words, the fact that sqrt(7)
by lmkg 13y ago
The rational roots of integers will cause interesting interactions, because when you multiply them you get back integers. In other words, the fact that sqrt(7) * sqrt(7) is an integer means that sqrt(7) interacts with the integers when you adjoin it. This is not the case for a transcendental number like pi.
More formally: This type of interaction is true for an irrational number if (and only if?) it is the root of a polynomial with integer coefficients. If you adjoin the root of a polynomial P(n) to the integers, the properties of the resulting set of numbers (e.g. factorization being unique) can be related back to properties of P(n). The nature of the connection has to do with the connection between a set of numbers and the set of polynomials of with coefficients from that set, and equivalence relations on that set of polynomials that are induced by P(n).
- simcop2387 13y agoI see that makes perfect sense. In this particular case because you end up doing multiplying by the compliment of the denominator to get rid of the root there, get a difference of squares that are both integers and easily end up with an integer on the denomiator of the fraction. leaving it all as trivially provable that you'll always end up with a rational number in the end (maybe not an integer).