3 ms·
Yeah, that's a more generic form of what I said. ok, hold on... e^(i*x)= cos(x)+i*sin(x) e^(-i*x)= cos(-x)+i*sin(-x)= cos(x)-i*sin(x) cos(x)= (1/2) * (e
by NAFV_P 13y ago
Yeah, that's a more generic form of what I said.
ok, hold on...
e^(i*x)= cos(x)+i*sin(x)
e^(-i*x)= cos(-x)+i*sin(-x)= cos(x)-i*sin(x)
cos(x)= (1/2) * (e^(i*x)+e^(-i*x))
sin(x)= (-i/2) * (e^(i*x)-e^(-i*x))
cos(i*x)= (1/2) * (e^(i*i*x)+e^(-i*i*x))=(1/2) * (e^x+e^(-x))
sin(i*x)= (-i/2) * (e^(x)-e^(-x))
That's the amusing part.