4 ms·
Yes but I think he is saying that if the left/what you compare to is not a constant then it will not warn you (if the type agrees, as it should anyway for a com
by rguldener 13y ago
Yes but I think he is saying that if the left/what you compare to is not a constant then it will not warn you (if the type agrees, as it should anyway for a comparison).
- cbhl 13y agoIf the left is a function call, it will still error out because you can't assign to it. If you're doing if (var1 == var2) then yoda expressions won't save you, however.
- koenigdavidmj 13y agoAlso, in C++ you can assign to the return value of a function returning a reference.