Happy to help! I am certainly not a master of bash/awk/sed scripting but I do find the ability to express very complex file operations in minimal characters ver

Happy to help! I am certainly not a master of bash/awk/sed scripting but I do find the ability to express very complex file operations in minimal characters very rewarding :). You will probably have to alias the script[0], as cd'ing in the script won't change the outside environment by default. I cut out a 'function' to make it one line, but I have attached the full source[1]. If you don't pass it any arguments it will tell you all of the available projects :). [0] Add something like this to your .bashrc alias project='. project' [1] The full source: #!/bin/bash if [[ $# -eq 0 ]] ; then awk '{print $1;}' ~/.projects exit 0 fi cd $(awk -v proj=$1 '$1 == proj { print $2; }' ~/.projects)