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I knew why I always hated these games, because there are some rules which apparently aren't a big deal, while others seem to matter a lot. In this case, the pr
by Udo 13y ago
I knew why I always hated these games, because there are some rules which apparently aren't a big deal, while others seem to matter a lot.
In this case, the problem asked for a precise solution, which was given in the resolution example, with no thought at all to that nagging little probability problem. So in order to "solve" this, I would have to know that everybody is basically supposed to disregard certain aspects of the problem. That's gotcha-type stuff that I always get wrong.
- chrismcb 13y agoWhat aspect is being disregarded? Previously you asked " Prisoner 2 is never at the switch at all before the Counter gets to his magic number" Except that if Prisoner 2 is never at the switch, the counter can never reach the magic number. Assume there are 3 prisoners (1,2,C), the magic number is 4. But if the sequence is 1,C,1,C,1,C.... The count will never be greater than 3 (2 is the switch starts as off) The warden said everyone will eventually visit the room. The one thing that was assumed (but not spelled out explicitly) is the game goes on forever. Which means at some point 2 visits the room a bunch of times, and then C will visit again, and will meet the magic number. Nothing to do with probability. And there is no guessing, 44 is a precise number.