2 ms·
The "buffer_ready" example was given as an incorrect use, though, which won't necessarily work even in a standards-conforming compiler, because the semantics of
by _delirium 13y ago
The "buffer_ready" example was given as an incorrect use, though, which won't necessarily work even in a standards-conforming compiler, because the semantics of volatile don't forbid reordering the loop (which has no volatile accesses) to go after the buffer_ready write.