4 ms·
Least bytes? var a=process.argv,i=a.length,x=0;while(i>2)x-=-a[--i];console.log(x)
by Scryptonite 13y ago
Least bytes?
var a=process.argv,i=a.length,x=0;while(i>2)x-=-a[--i];console.log(x)
- jamescarl 13y agoThat's a neat approach! Thanks
4 ms·