3 ms·Σ(2^i / (10^(5i)) = Σ(2/10^5)^i = 1/(1-(2/10^5)) = 10000/9998 (you get the idea)by emillon 13y agoΣ(2^i / (10^(5i)) = Σ(2/10^5)^i = 1/(1-(2/10^5)) = 10000/9998 (you get the idea)