3 ms·
It would look like result = range(1, 3).concat(range 4, 6).map((x) -> x * x).filter (x) -> x % 2 is 0 or result = range 1, 3 result = result.conc
by ndnichols 13y ago
It would look like
result = range(1, 3).concat(range 4, 6).map((x) -> x * x).filter (x) -> x % 2 is 0
or
result = range 1, 3
result = result.concat range 4, 6
result = result.map (x) -> x * x
result = result.filter (x) -> x % 2 is 0