> Haskell, by its lazy evaluation, is basically a macro-only language This is not correct. To understand why, please see Ryan Culpepper's answer to this SO que

> Haskell, by its lazy evaluation, is basically a macro-only language This is not correct. To understand why, please see Ryan Culpepper's answer to this SO question: http://stackoverflow.com/questions/7046950/lazy-evaluation-vs-macros/7047413#7047413 http://stackoverflow.com/questions/7046950/lazy-evaluation-v...