4 ms·

I'm getting x = 11/3 as well. My workings: (x-3)/(x-1) = (x-4)/(x-5) (x-3)(x-5) = (x-4)(x-1) x^2 -8x + 15 = x^2 -5x +4 -8x + 11 = -5x 11 = 3x x = 11/3 F

by redcap 17y ago

I'm getting x = 11/3 as well. My workings: (x-3)/(x-1) = (x-4)/(x-5) (x-3)(x-5) = (x-4)(x-1) x^2 -8x + 15 = x^2 -5x +4 -8x + 11 = -5x 11 = 3x x = 11/3 FWIW, wolfram alpha agrees with me.

deleted 17y ago
[deleted]
bobbyi 17y ago
You changed the equation. You started with (x-3)/(x-1) = (x-4)/(x-5) which is not the same as x - 3/x - 1 = x - 4/x - 5 , the equation in the submission.
- redcap 17y ago
  Haha, thanks - I guess the problem is in my parsing :)