4 ms·
They are not redundant. Any string of one or more exes is going to constrain a substring of exes of length 2^n (consider n=0 for a trivial proof), so you do nee
by alanh 13y ago
They are not redundant. Any string of one or more exes is going to constrain a substring of exes of length 2^n (consider n=0 for a trivial proof), so you do need those anchors!
- rplnt 13y agoI meant my previous post where I had them in every single possibility.