3 ms·
(sorry to see you downvoted - because it is actually sometimes tought to grasp but...) it doesnt approach one- your thinking of a nice graph where the line do
by ErrantX 17y ago
(sorry to see you downvoted - because it is actually sometimes tought to grasp but...)
it doesnt approach one- your thinking of a nice graph where the line does approach but never touch, however 0.9... is NOT a function, cannot be plotted. It exists for infinite length.
Any distance it is from 1 is constant.
- dickwad 17y agoyes and sometimes the integrals of those graphs converge on a value...
- grandalf 17y agoI interpreted repeating 9's as: the function that writes some number of repeating 9's (replacing the zero in the last decimal place with a 9). This function approaches 1, does it not? f(1) = 0.9 f(2) = 0.99 f(3) = 0.999 so f as defined above approaches 1 I interpreted the question in the context of numerical precision. Since we are usually not dealing with infinite precision, the two are not equal. I am familiar with the obvious: 1/3 == 0.3333... and 3 * 1/3 == 1 so 0.9999... == 1
- darkxanthos 17y agoahhh No the OP was referring to the value at the limit as x->inf of your function f.