3 ms·
power series. 0.999... = sigma 9/10^n n=1 -> inf = 9 * sigma 1/10^n n=1 -> inf = 9 * ((sigma 1/10^n n=0 -> inf) - 1) = power series sigma 1/10^n n=0 -> inf =
by dnaquin 17y ago
power series.
0.999... = sigma 9/10^n n=1 -> inf = 9 * sigma 1/10^n n=1 -> inf = 9 * ((sigma 1/10^n n=0 -> inf) - 1) =
power series sigma 1/10^n n=0 -> inf = 1/(1-1/10)
= 9 * (1/(1-1/10) - 1) = 1
qed.