3 ms·
This is already the case in Haskell. Look up functor
by rian 13y ago
This is already the case in Haskell. Look up functor
- quatrevingts 13y agoNo, fmap is still an explicit operation.
- hopp_check 13y agoThere should be some degree of explicitness so that when you look at the code a year later it doesn't look like voodoo magic.