3 ms·
The two envelopes paradox is a good one: http://consc.net/papers/envelope.html http://consc.net/papers/envelope.html And another that I've figured out the "ri
by drblast 13y ago
The two envelopes paradox is a good one:
http://consc.net/papers/envelope.html http://consc.net/papers/envelope.html
And another that I've figured out the "right" answer to but think there might be more to it is this:
Suppose I set up a two-player game as follows:
1. One player is the "odd" player, the other is
the "even" player.
2. Each player may choose a single number per turn,
either one or two.
3. The result of each turn is the sum of the two players'
choices. For example, if the even player picks 1 and the
odd player picks 2, the result of that turn is 3.
4. If the result is odd, the even player pays the odd
player that amount, and vice-versa. In our example
result of 3, the even player would pay the odd player 3
dollars.
Question: Is this game fair? If not, is it possible to give either player a per-turn stipend to make the game fair? If so, how much is that amount?
- tomca32 13y agoI'll bite. I guess that the odd player can always choose 1. In that case he can either win 3 or lose 2. Making that the favorable choice for the odd player. Even player could always choose 2 in which case he can either win 4 or lose 3. Making this the favorable choice for the even player. However, if both players play their favorable choice, odd player always wins: 2 + 1 = 3. I'm not sure if I got this right, but that's my thinking so far...
- drblast 13y agoHere's a hint; is there a strategy one player can play such that no matter what the other player does, the first will win money on average?