3 ms·
I suspected that time difference between falls would be not linear, but I was not sure about actual ratio. Playing with freefall distance equations showed that
by dennisgorelik 13y ago
I suspected that time difference between falls would be not linear, but I was not sure about actual ratio.
Playing with freefall distance equations showed that time to fall difference is square root of 6. Here we are:
Height = gEarth*timeOnEarth^2/2 = gMoon*timeOnMoon^2/2
gEarth = gMoon * 6
6 * gMoon * timeOnEarth^2/2 = gMoon * timeOnMoon^2/2
6 * timeOnEarth^2 = timeOnMoon^2
timeOnMoon = sqrt(6 * timeOnEarth^2)
timeOnMoon = sqrt(6) * timeOnEarth = 2.45 * timeOnEarth