2 ms·
It is implementation-specific (from the spec:) There is also a set of predeclared numeric types with implementation-specific sizes: uint either 32 or 64 b
by aaronblohowiak 13y ago
It is implementation-specific (from the spec:)
There is also a set of predeclared numeric types with implementation-specific sizes:
uint either 32 or 64 bits
int same size as uint
uintptr an unsigned integer large enough to store the uninterpreted bits of a pointer value