3 ms·
Average isn't relevant in this case. What you want is percent of Attempts over 7 yards (which is more akin to median). Four zero yard plays + Four five yard p
by jcampbell1 13y ago
Average isn't relevant in this case. What you want is percent of Attempts over 7 yards (which is more akin to median).
Four zero yard plays + Four five yard plays + two 25 yard plays = 7 yards per attempt, but a 20% success rate.