2 ms·
Maybe I am looking at this differently, but I would say that by definition what you describe makes $field_b harder than $field_a. I don't think the difficulty
by vonmoltke 13y ago
Maybe I am looking at this differently, but I would say that by definition what you describe makes $field_b harder than $field_a. I don't think the difficulty of the field has any bearing on its worthiness, though.