3 ms·
Also 0xCC is the breakpoint opcode (INT3) on x86 architecture, so if the program were to start executing at that point, the debugger would be notified (or proba
by quasque 13y ago
Also 0xCC is the breakpoint opcode (INT3) on x86 architecture, so if the program were to start executing at that point, the debugger would be notified (or probably an immediate application crash if no debugger attached).