rachelbythebay didn't say it only applies to one implementation. She said it was implementation specific. A subtle distinction, but she's correct. Just because

rachelbythebay didn't say it only applies to one implementation. She said it was implementation specific. A subtle distinction, but she's correct. Just because something is fundamentally a 32-bit number, that doesn't automatically mean that all possible representations of that number will be converted to it. They have to be implemented to do so.