3 ms·
No, it is exponential in the number of digits of accuracy as a function of the number of iterations performed.
by dreish 17y ago
No, it is exponential in the number of digits of accuracy as a function of the number of iterations performed.
- lkozma 17y agoYes, but I think this is what is called quadratic convergence if the exponent is 2, as it is here. See for ex. http://sepwww.stanford.edu/public/docs/sep97/paul1/paper_html/node5.html http://sepwww.stanford.edu/public/docs/sep97/paul1/paper_htm...
- jonsen 17y agoDon't cross purpose each other. In fact it's somewhat interesting, that quadratic error decay equals exponential precision growth: 0.1^2 = 0.01 0.01^2 = 0.0001 0.0001^2 = 0.00000001 ... Value equals error; number of zeros equals precision measured as number of digits.