3 ms·

If we want to golf it, it would probably just be lines = IO.readlines ARGV[0] File.write ARGV[1], lines.sort.join('\n') certainly more readable than the C

• danmaz74 13y ago
  Well, if you really want to golf it, you can just write: File.write ARGV[1], IO.readlines(ARGV[0]).sort.join('\n') ;)
  • Freaky 13y ago
    You're fired. IO.write(ARGV[1], ARGF.lines.sort.join)
    • Aaronneyer 13y ago
      I believe you still need to join on newline, the default is space. However you can save a couple characters by using `$*` instead of ARGV. Also, trim out the space between the arguments and kill the parenthesis for the optimal golfing.
    • danmaz74 13y ago
      Wow, this is really sweet and esoteric (didn't know about ARGF) - but, reading the docs for ARGF, wouldn't it also try to ready from ARGV[1]? Maybe this would fix it: IO.write(ARGV.pop, ARGF.lines.sort.join('\n'))
      • Freaky 13y ago
        Yes, good catch. join('\n') is wrong though - IO#lines preserves newlines, the default join is the empty string, and you meant "\n" :)
        • danmaz74 13y ago
          :)
    • Aaronneyer 13y ago
      Here's the shortest I've gotten after looking at some of the comments: IO.write$*.pop,ARGF.lines.sort.join And yes, it does work even without the space between `write` and `$*`. Also after testing, I realized the ('\n') is not required for join. When you call 'lines', it still has the '\n' character in the string, and when you join, it defaults to join without a delimiter, so it's putting them back together with the newline still there.
• trentmb 13y ago
  Is > File.write ARGV[1], (IO.readlines ARGV[0]).sort.join('\n') not valid Ruby?
  • rofrol 13y ago
    File.open(ARGV[1], 'w') { |file| file.write(File.read(ARGV[0]).lines.sort.join) } http://stackoverflow.com/questions/8278680/ruby-undefined-method-write-for-ioclass-nomethoderror http://stackoverflow.com/questions/8278680/ruby-undefined-me...