3 ms·
Consider a polar vector, which possesses a magnitude and one or more angles. For such a vector, the magnitude is always positive, on the basis that it is define
by lutusp 13y ago
Consider a polar vector, which possesses a magnitude and one or more angles. For such a vector, the magnitude is always positive, on the basis that it is defined this way when shaped from Cartesian elements:
m = sqrt(x^2 + y^2 + z^2 ...)
In this convention, for any given value of m, the signs of the individual components are lost in the conversion, which means when discussing magnitude, only the absolute value of m matters.
But, because Mathematica has a "Greater[]" function, and because that function simultaneously uses the word I chose and pays attention to scalar signs, I must be wrong about this.
> That seems an odd definition of "greater" ...
I respect the people behind Mathematica, so I have to agree -- it's not what I thought. I should have qualified what I said more carefully.