5 ms·
For a 1MB JPEG, that'd be over 8 million different images.
by JosephRedfern 13y ago
For a 1MB JPEG, that'd be over 8 million different images.
- nitrogen 13y agoIf you could point to a region of the image where the corruption begins, you would reduce the number of possible images significantly.
- porges 13y agoThat sounds plausible. Another idea: choose a section of "bad image" and a section of "good image" which should have similar colours and then generate mutations of the corrupted DCT square until you have a close match between the two areas.
- aninhumer 13y agoGiven that we're assuming some kind of correctness metric for the final image, could we not also use this metric to locate the start of the corruption?