3 ms·

Unless I'm being daft, it can't be reduced to that at all. Dropping matching brackets, removing redundant {1,1} blocks, and escaping the \. we get down to:

Unless I'm being daft, it can't be reduced to that at all. Dropping matching brackets, removing redundant {1,1} blocks, and escaping the \. we get down to: ^[A-Za-z]([A-Za-z]+|\d+)@[A-Za-z]+\.[A-Za-z]+$ Your version isn't the same at all - \w allows letters digits and underscores anywhere, whereas the original is more subtle.

simpleigh 13y ago
... and ignoring case obviously gets us down here: ^[a-z]([a-z]+|\d+)@[a-z]+\.[a-z]+$
- irahul 13y ago
  Yes. If you are going for equivalent, this would be it: pat = re.compile(r'^ [a-z] [a-z0-9]* @ [a-z]+ \. [a-z]+ $', re.I | re.X) I took a few liberties in crafting the reduction.