3 ms·

Haha. I feel very silly now. I was just about to respond with the same thing. while True: result = list(islice(iterator, 3)) if not result:

by signed0 13y ago

Haha. I feel very silly now. I was just about to respond with the same thing. while True: result = list(islice(iterator, 3)) if not result: break yield result

StavrosK 13y ago
That's what I did, I edited my post above. It's around 23x slower, although I had to use a function invocation for %timeit as well, so it's probably a bit faster in practice.
- signed0 13y ago
  One more for kicks: n = iter(array).next [(n(), n(), n()) for _ in xrange(len(array) / 3)]