3 ms·
I am not sure if I understood you correctly, so let me check: Did you mean that stupidlyExpensiveCalculation() will be always executed, regardless if debugging
by asmosoinio 17y ago
I am not sure if I understood you correctly, so let me check: Did you mean that stupidlyExpensiveCalculation() will be always executed, regardless if debugging is enabled?
Seems to me you say this like it's a good thing. Or I am misunderstanding...