3 ms·
Multiplying both sides by zero is always legitimate (if rarely useful). In the example linked, the error is in dividing by zero. More specifically, in dividing
by gizmo686 13y ago
Multiplying both sides by zero is always legitimate (if rarely useful). In the example linked, the error is in dividing by zero. More specifically, in dividing by (a-x). Formally speaking, this operation is only defined when (a-x)!=0. Mutipling by zero is defined for all real numbers.
- lutusp 13y agoThe parallel I was making is that a numerical term invalidated an equation, rendered it meaningless, not that the circumstances were identical.