3 ms·
Because if foo contains "f" and bar contains "b", then your scheme would have (foo + " " + bar) contain "fb" and not "f b"
by shrughes 17y ago
Because if foo contains "f" and bar contains "b", then your scheme would have (foo + " " + bar) contain "fb" and not "f b"
- stcredzero 17y agoThen the fool should use a regular String! RTFM!