5 ms·
That's the amount of energy needed to bring nearly 1000 kg of water from 25°C to 100°C, but not enough to begin the phase transition from liquid to gas (i.e. st
by ErsatzVerkehr 13y ago
That's the amount of energy needed to bring nearly 1000 kg of water from 25°C to 100°C, but not enough to begin the phase transition from liquid to gas (i.e. start boiling).
The heat of vaporization of water (i.e. the amount of energy required to convert liquid water at 100°C to vapor at the same temperature) is 2260 J/g. So to completely boil your metric ton of water at 100°C would require an additional 1000 kg * (2260 J/g) = 2.3 GJ, which is 627 kWh!
At 85 kWh, the Tesla's battery contains enough energy to completely boil off 119 kg of water starting at 25°C [0], which is still pretty impressive!
[0] 85 kWh / ((4.181(J/(g * K)) * 75 K) + (2260 J/g))
- jlgreco 13y agoAh very true. Knew I was forgetting something.
- chongli 13y agoWhile that's true, I don't think it's what the parent meant. Colloquially, when we say to boil water we don't mean until the vessel is dry, just until a roiling boil is reached (this is typically how we cook pasta).
- ErsatzVerkehr 13y agoIf the 1000 kg is heated uniformly, this is not enough energy to bring it to a "roiling boil". There will be no bubbles.
- chongli 13y agoRight. It's a good thing stoves/ranges heat from the bottom!
- ErsatzVerkehr 13y agoYou're forgetting convection.