3 ms·

Though, the contract you have with TCP , is between TCP at your end and the TCP at the peer, not that it also have delivered the data to the application of the

Though, the contract you have with TCP , is between TCP at your end and the TCP at the peer, not that it also have delivered the data to the application of the peer. If the peer crashes just as it read() the data, but didn't process it, it will look just as a normal clean close on the sender machine if there arn't more data laying around in the TCP buffers.

tptacek 13y ago
To be clear, you're talking about the case where the application dequeues the data from its receive queue and then crashes. If you close a socket without reading queued data, you get an RST.