4 ms·
sqrt(h^2 + h^2)*2 is the max length if your box is 0 is width. The max possible length decreases with sqrt(w^2 + w^2) as width expands. Assumed the hallways si
by stelund 17y ago
sqrt(h^2 + h^2)*2 is the max length if your box is 0 is width. The max possible length decreases with sqrt(w^2 + w^2) as width expands.
Assumed the hallways size is symetrical and your object cannot be tilted to achive a smaller length. For example, an object of little height in a high to ceiling room will be possible to tilt with the same measurements are presented above (pythagoras). But if the box has any substancial height you wont get any help from a tilt. A soffa would tilt, a dish washer does not.