4 ms·
updated my comment. The only thing I can think of is that discrete logs don't work that way. while E^(e.log_E(M)) == E mod n, e.log_E(M) doesn't equal 1. And
by jaekwon 13y ago
updated my comment.
The only thing I can think of is that discrete logs don't work that way.
while E^(e.log_E(M)) == E mod n, e.log_E(M) doesn't equal 1.
And I'm not sure what /e means in the realm of exponents, besides *d, and I don't know how to find d without knowing M.