3 ms·
I think you're off by a factor of 1000. I get 980 terawatt-hours of energy. If, as you say, 971 GWh is equivalent to 6% of total energy usage, then 980 TWh is
by tanzam75 13y ago
I think you're off by a factor of 1000. I get 980 terawatt-hours of energy.
If, as you say, 971 GWh is equivalent to 6% of total energy usage, then 980 TWh is 6000% total energy usage. Of course, you don't get 100% efficiency in incineration, but an oversupply of 60x leaves a lot of room for inefficiency.
Here's my calculation. I've used scientific notation to reduce the possibility of order-of-magnitude errors:
> 230 million tons Avoirdupois = 2.3e8 tons
> 2.3e8 tons * 2e3 pounds/ton = 4.6e11 pounds
> 4.6e11 pounds * 0.45 kg/pound = 2.07e11 kg
> 2.07e11 kg * 1000 g/kg = 2.07e14 g
> 2.07e14 g * 17 kJ/g for carbohydrates = 3.52e15 kJ
> 3.52e15 kJ * 2.78e-4 kWh/kJ = 9.8e11 kWh
That's 980 billion kWh, or 980 million MWh, or 980 thousand GWh, or 980 TWh.
I wonder if maybe you're getting nutrition Calories (uppercase) confused with gram calories (lowercase). Nutrition Calories are actually kilocalories!!! If you forgot to multiply by 1000 to account for this, then that would explain your result.
In Europe, nutrition labels are listed in kilojoules. This eliminates the confusion over calories.
- dredmorbius 13y agoI'll double-check my math, but suspect my numbers are closer to the truth. Keep in mind that you're also limited by heat-engine efficiencies. I need to double-check if steam turbines are governed by Carnot cycle (35% max efficiency) or others, but that's another factor to keep in mind. And yes, the calorie/kilocalorie distinction is important ;-)
- tanzam75 13y agoIf you've got 6000% the required energy, then 35% efficiency is not of major concern. Three orders of magnitude makes a world of difference.
- dredmorbius 13y agoIt does. And I'm confirming your numbers, FWIW, which makes me suspect there's something wrong with my assumptions. I'll see if I can't dig up other references on waste-to-energy estimates.