3 ms·x<1>=x and by induction x<n+1>=x^x<n> How does one induct (induce?) this?by snake_plissken 13y agox<1>=x and by induction x<n+1>=x^x<n> How does one induct (induce?) this?tomrod 13y agoProve it for the base case (x<1> = x), then assume it works for n-1, and show it works for the nth case.qiemem 13y agoGro-Tsen is just defining x<n> recursively. "by induction" there doesn't mean "proof by induction".