4 ms·
Isn't the point that these things do not have much kinetic energy at all? The whole scheme wouldn't make sense if you still had to invest the same amount of pow
by revelation 13y ago
Isn't the point that these things do not have much kinetic energy at all? The whole scheme wouldn't make sense if you still had to invest the same amount of power as for a conventional train.
- SlyShy 13y agoKinetic energy = 1/2 m * v^2. Hyperloop trains wouldn't have "much" less energy, because the scaling factor on velocity is so high that your savings on train weight don't mean much. You are right that it would take less power.
- ajuc 13y agoSavings would be on the air friction, and the power you need to overcome it along the way.