4 ms·
To the compiler, it shouldn't care where a label exists. If you're telling it to go to label L:, execution will jump there. GCC appears to look out for the prog
by apaprocki 13y ago
To the compiler, it shouldn't care where a label exists. If you're telling it to go to label L:, execution will jump there. GCC appears to look out for the programmer and always prints an error (and I don't see an option to shut it off). Oracle Studio compiles it with no issue and the above statement returns 1.