3 ms·
that...isn't true. The standard form of Euler's identity is e^(iπ) + 1 = 0. Of course, all the cool kids nowadays use e^(iτ) = 1. ;)
by nemo1618 13y ago
that...isn't true. The standard form of Euler's identity is e^(iπ) + 1 = 0.
Of course, all the cool kids nowadays use e^(iτ) = 1. ;)
- revskill 13y agoOhh, my mistake. Thank you for correction.