3 ms·

I think it's easier to think about it as if you are just multiplying the original equations by some power of alpha or beta i.e. alpha^(n-2)(alpha^2 - 6alpha -

• tzs 13y ago
  > Hard to see without latex typing... MathJax to the rescue: \[\alpha^{n-2}(\alpha^2-6\alpha-2)=0=\alpha^{n}-6\alpha^{n-1}-2\alpha^{n-2}\] To render with MathJax, use the bookmarklet available here: http://checkmyworking.com/misc/mathjax-bookmarklet/ http://checkmyworking.com/misc/mathjax-bookmarklet/