5 ms·
If --hidden-encrypt-to is used, there still will be signs of that. Specifically, the message addressed to 0x0000000 and the recipient will basically brute force
by unsignedint 13y ago
If --hidden-encrypt-to is used, there still will be signs of that. Specifically, the message addressed to 0x0000000 and the recipient will basically brute force it uses every key he/she has.
Having said, that, according to PGP Dump
Old: Public-Key Encrypted Session Key Packet(tag 1)(524 bytes)
New version(3)
Key ID - 0x5B50940B79DEBE35
Pub alg - RSA Encrypt or Sign(pub 1)
RSA m^e mod n(4096 bits) - ...
-> m = sym alg(1 byte) + checksum(2 bytes) +
PKCS-1 block type 02
New: Symmetrically Encrypted and MDC Packet(tag 18)(4096
bytes) partial start
Ver 1
Encrypted data [sym alg is specified in pub-key
encrypted session key]
(plain text + MDC SHA1(20 bytes))
New: (1024 bytes) partial continue
New: (18 bytes) partial end
It looks like we can merely see that the message is destined to 0x5B50940B79DEBE35. We won't be able to tell who's signer until it is decrypted.
- cdjk 13y agoAh, thanks. I learned something new today.
- deleted 13y ago[deleted]
- deleted 13y ago[deleted]