3 ms·
Well, one of my friends drop me one formula. Let x to be the rate of GC time out of total running time, and we can get (1-2x) * 14 = 1- x => x = 13/27 which m
by jacktang 17y ago
Well, one of my friends drop me one formula. Let x to be the rate of GC time out of total running time, and we can get
(1-2x) * 14 = 1- x => x = 13/27
which means now ruby spends 13/27 time on GC, fast enough? (before patch, it spends 26/27 time on GC, really bad)
- dfranke 17y agoI don't see how you're getting this formula, but if it spends 13/27 on GC after a 2x GC speedup, then it was 26/40 before, not 26/27.